Respuesta :

arthurpdc
The conjugate of a complex number [tex]z=a+bi~(a,b\in\mathbb{R})[/tex] is [tex]\overline{z}=a-bi[/tex]. So, for the complex[tex]z=4-3i[/tex], the conjugate is [tex]\overline{z}=4+3i[/tex].
calculista

Answer:

[tex]4+3i[/tex]

Step-by-step explanation:

we know that

To find the conjugate complex of a complex number, simply change the sign of the imaginary part of the complex number

In this problem we have

[tex]4-3i[/tex]

so

the complex conjugate is equal to

[tex]4+3i[/tex]