Answer:
The required probability is 0.1.
Step-by-step explanation:
red balls = 3
yellow balls = 2
blue balls = 5
Selected balls = 5
Number of elemnets in sample space = 10 C 5 = 1260
Ways to choose 1 red ball and 4 other colours = (3 C 1 ) x (7 C 4) = 105
Ways to choose 5 balls of other colours = 7 C 5 = 21
So, the probability is
[tex]\frac{105}{1260} + \frac {21}{1260}\\\\\frac{126}{1260}=0.1[/tex]
