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Find the limit. use l'hospital's rule if appropriate. if there is a more elementary method, consider using it. lim x→4 x2 − 16 x2 − 4x

Respuesta :

LammettHash
Probably you are supposed to compute

[tex]\displaystyle\lim_{x\to4}\frac{x^2-16}{x^2-4x}[/tex]

Factorize the numerator and denominator, then simplify:

[tex]\displaystyle\lim_{x\to4}\frac{(x-4)(x+4)}{x(x-4)}=\lim_{x\to4}\frac{x+4}x=\frac{4+4}4=2[/tex]

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